A-level · Beta

Binomial distribution

Move the success probability, select outcomes and build cumulative events.

Drag P on the probability track. Select a bar or use the outcome slider to choose k.

P(X=k)=(nk)pk(1−p)n−kP(X=k)=\binom nk p^k(1-p)^{n-k}
Binomial probabilities and draggable success probability.10.50ProbabilityP(X = 0) = 0.0009765630P(X = 1) = 0.009765631P(X = 2) = 0.04394532P(X = 3) = 0.1171883P(X = 4) = 0.2050784P(X = 5) = 0.2460945P(X = 6) = 0.2050786P(X = 7) = 0.1171887P(X = 8) = 0.04394538P(X = 9) = 0.009765639P(X = 10) = 0.00097656310mean 501P

Tab to a ring or outcome, then use the arrow keys. Sliders also work with touch and keyboard.

Shaded bars make up the selected event. The dashed green line marks np.

Selected event
P(X=5)≈0.246094P(X=5)\approx 0.246094
Expected value
5
Variance
2.5

Use this model for a fixed number of independent trials, two outcomes and a constant success probability. Decimal probabilities are approximate.

Predict, test and explain

Step 1 of 3

Predict

If X is binomial with n = 4 and p = ½, what is P(X = 2)?

InvestigateKeep n fixed and change p to 1 − p. How does the chart change?

Explore and compare

Choose the investigation above. Predict what will change before you move a control.

Try it in the simulation. Change one thing at a time.

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Hints, self-check and connections
Try a self-check

Fixed values, separate from the diagram controls.

If X is binomial with n = 4 and p = ½, what is P(X = 2)?

X∼Bin(4,12),P(X=2)X\sim\mathrm{Bin}(4,\tfrac12),\quad P(X=2)

Hint

There are a fixed number of independent trials with constant p.

Reveal answer

There are 6 ways to choose two successes; each specific outcome has probability 1/16.

38\frac38

Build an explanation

Hint 1

There are a fixed number of independent trials with constant p.

Hint 2

For exactly k successes, use n choose k times pᵏ(1 − p)ⁿ⁻ᵏ.

Hint 3

A cumulative event adds several disjoint outcome probabilities.

Worked example

This example uses fixed values, separate from the diagram controls.

Find P(X = 2) for X ~ Bin(4, ½).

  1. Choose which two trials succeed: 4 choose 2 = 6.
  2. Each ordered outcome has probability (1/2)⁴ = 1/16.
  3. Multiply 6 by 1/16 and simplify.

Answer: 3/8.

Connect this idea

Watch out: The mean np = 2 is a value, not a probability.

Specification and learning route

AQA N1 · Edexcel Statistics 4.1

AS and A-level. This model illustrates selected content; references are not a claim of full coverage or exam-board endorsement.

Useful starting knowledge: Probability; Independent trials; Combinations; Discrete random variables.

AQA specification · Edexcel specification